Example question: A gas reaction took place at 400K at 20 Pa, in a container with the volume of 150 metres cubed. With the relative number of 8.314 JK mole to the power of minus 1. How many moles of gas were present?
We know the ideal gas equation so we can just minipulate it to work out n.
So PV=nRT now becomes n= RT/PV.
So we can now subsitute the numbers into the equation.
So n=8.314 x 400/20x150.
Which makes n to be 1.19 moles of gas to 2 decimal places.
Comments
No comments have yet been made