Chemistry: Year 9 Term 3: Equations 0.0 / 5 ? ChemistryCalculations, moles and yieldGCSEAQA Created by: Charlotte HerondaleCreated on: 31-03-18 10:05 Mass = Moles x Mr 1 of 12 Moles = Mass / Mr 2 of 12 Mr = Mass / Moles 3 of 12 Percentage of element in formula = (Mass of element / Mass of molecule) x 100 4 of 12 Percentage yield = (Actual mass / Maximum theoretical mass) x 100 5 of 12 Atom economy = (Mass of desired product / Sum of masses of reactants) x 100 6 of 12 (MCV) Moles = Concentration x Volume 7 of 12 Concentration = Moles / Volume 8 of 12 Volume = Moles / Concentration 9 of 12 Relative isotopic mass = (% abundance x Ar) + (% abundance x Ar) / 100 10 of 12 Moles of gas = Volume / 24dm3 11 of 12 Volume of gas = Moles / 24dm3 12 of 12
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